Rationalise the Denominator April 23, 2021April 21, 2021 by user 2011 May June Paper 21 Q1 Without using a calculator, express (5+2√3)22+√3 in the form p+q√3, where p and q are integers. Answer (5+2√3)22+√3=(25+20√3+12)(2−√3)(2+√3)(2−√3)=(37+20√3)(2−√3)4−3=74−37√3+40√3−60=14+3√3 2014 May june Paper 21 Q2 Without using a calculator, express 6(1+√3)−2 in the form a+b√3, where a and b are integers to be found. Answer 6(1+√3)−2=6(1+√3)2=61+2√3+3=64+2√3=32+√3⋅2−√32−√3=6−3√31=6−3√3 More Similar Questions 2012 Oct Nov Paper 23 Q3 Without using a calculator, simplify (3√3−1)22√3−3, giving your answer in the form a√3+b3, where a and b are integers.Answer Available soon 2013 Oct Nov Paper 21 & 22 Q2 Express (4√5−2)2√5−1 in the form p√5+q, where p and q are integers.Answer Available soon 2014 May June Paper 22 Q1 Without using a calculator, express (2+√5)2√5−1 in the form a+b√5, where a and b are constants to be found.Answer Available soon 2016 May June Paper 21 & 23 Q5 Do not use a calculator in this question.(a) Express √8√7−√5 in the form √a+√b, where a and b are integers. Answer Available soon 2016 Oct Nov Paper 23 Q1 Without using a calculator, show that √5+3√3√5+√3=√k−2 where k is an integer to be found. Answer Available soon