## Cambridge Additional Mathematics 0606 : 2023 October-November Paper 23 Q9 (Solution)

Question 9(a) Find (frac{dy}{dx}) Steps of Solution Given ( y = xe^{2x} ): [frac{dy}{dx} = x cdot frac{d}{dx}(e^{2x}) + e^{2x} cdot frac{d}{dx}(x)][frac{dy}{dx} = x cdot 2e^{2x} + e^{2x} cdot 1][frac{dy}{dx} = 2xe^{2x} + e^{2x}][frac{dy}{dx} = e^{2x}(2x + 1)] Explanation of the Steps Given the function ( y = xe^{2x} ), we need to find its … Read more