Certainly! Here are the modified questions with the answers enclosed in the appropriate tags:
a. Factorise a2+4a
a(a+4)
b. Factorise 3x+4x2
\(x(4x + 3)\”)
c. Factorise 4x2–x
\(x(4x – 1)\”)
d. Factorise 7x–3x2
\(x(7 – 3x)\”)
e. Factorise 2x2+4x
\(2x(x + 2)\”)
f. Factorise 6x–3x2
\(-3x(x – 2)\”)
g. Factorise 12x+16x3
\(4x(3 + 4x^2)\”)
h. Factorise 25x2–15x3
\(5x^2(5 – 3x)\”)
i. Factorise 30x3+10x2
\(10x^2(3x + 1)\”)
j. Factorise 80y3–30y2
\(10y^2(8y – 3)\”)
k. Factorise 12x+15x2–18x3
\(-3x(6x^2 – 5x – 4)\”)
l. Factorise 4a3–6a+8a2
No further factorization possible.
x={2}{7}/{9}
x = 31/4 + 71/2
(x+3)2 = 7/3
(x+3) / 2 = 7 / 3