Certainly! Here are the modified questions with the answers enclosed in the appropriate tags:
a. Factorise \(a^2 + 4a\)
\(a(a + 4)\)
b. Factorise \(3x + 4x^2\)
\(x(4x + 3)\”)
c. Factorise \(4x^2 – x\)
\(x(4x – 1)\”)
d. Factorise \(7x – 3x^2\)
\(x(7 – 3x)\”)
e. Factorise \(2x^2 + 4x\)
\(2x(x + 2)\”)
f. Factorise \(6x – 3x^2\)
\(-3x(x – 2)\”)
g. Factorise \(12x + 16x^3\)
\(4x(3 + 4x^2)\”)
h. Factorise \(25x^2 – 15x^3\)
\(5x^2(5 – 3x)\”)
i. Factorise \(30x^3 + 10x^2\)
\(10x^2(3x + 1)\”)
j. Factorise \(80y^3 – 30y^2\)
\(10y^2(8y – 3)\”)
k. Factorise \(12x + 15x^2 – 18x^3\)
\(-3x(6x^2 – 5x – 4)\”)
l. Factorise \(4a^3 – 6a + 8a^2\)
No further factorization possible.
x={2}{7}/{9}
x = 31/4 + 71/2
(x+3)2 = 7/3
(x+3) / 2 = 7 / 3