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The diagram shows a handle with three forces, each \(100 \mathrm{~N}\), applied to it. The handle is free to move.
What is the effect of the forces on the handle?
The diagram shows a man holding a sack and barrow stationary. He applies a vertical force to the handle.
The centre of mass and the weight of the sack and barrow are shown. The wheel acts as a pivot.
What is the mannitude of the vertical force exerted by the man?
The diagram shows a uniform metre rule pivoted at the \(30 \mathrm{~cm}\) mark.
The rule balances when a weight of \(6.0 \mathrm{~N}\) is hanging from the zero mark and a weight of \(2.0 \mathrm{~N}\) is hanging from the \(70 \mathrm{~cm}\) mark.
What is the weight of the rule?
The diagram shows a uniform bar of length \(120 \mathrm{~cm}\) and weight \(W\). The bar is pivoted at a point \(40 \mathrm{~cm}\) from the left end of the bar.
A load of \(\frac{W}{2}\) is suspended from the right-hand end of the bar.
A downward force \(F\) is applied to the left-hand end of the bar to keep it in equilibrium.
What is the magnitude of force \(F\) ?
A beam of weight \(6.0 \mathrm{~N}\) is suspended from two strings \(P\) and \(Q\).
String \(P\) is \(30 \mathrm{~cm}\) from the left-hand end of the beam, as shown. String \(Q\) is not shown.
The tension in string \(\mathrm{P}\) is \(2.0 \mathrm{~N}\).
What is the tension in string \(Q\) and where is it attached so that the beam is in equilibrium?
The diagram shows a uniform metre rule. The rule is pivoted at its mid-point. A downward force of \(4.0 \mathrm{~N}\) acts on the rule at the \(5 \mathrm{~cm}\) mark. The rule is held by a string at the \(30 \mathrm{~cm}\) mark. The rule is in equilibrium.
What is the upward force that the string exerts on the rule?
The diagram shows a trolley used to transport a load of \(400 \mathrm{~N}\).
A force \(F\) vertically downwards is needed to balance the trolley as shown.
The centre of mass of the trolley is vertically above the pivot.
What is the value of \(F\) ?
A beam pivoted at one end has a force of \(5.0 \mathrm{~N}\) acting vertically upwards on it as shown. The beam is in equilibrium.
What is the weight of the beam?
A long plank \(X Y\) lies on the ground. A load of \(120 \mathrm{~N}\) is placed on it, at a distance of \(0.50 \mathrm{~m}\) from end\(X\), as shown.
End \(Y\) is lifted off the ground. The upward force needed to do this is \(65 \mathrm{~N}\).
In the diagram, \(W\) is the weight of the plank, acting at its mid-point.
What is the value of \(W ?\)
The diagram shows a non-uniform beam of weight \(120 \mathrm{~N}\), pivoted at one end. The beam is kept in equilibrium by force \(F\).
What is the value of force \(F\) ?